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  1. Observium
  2. OBS-2901

graph.php showing zero agregate bps value for now in multi-port_bits* graphs

Details

    • Bug
    • Resolution: Fixed
    • Major
    • None
    • Professional Edition
    • API
    • None

    Description

      eg. /graph.php?type=multi-port_bits_duo_separate&id=26475,26299 shows zero agregate bps for "now"

      Output attached

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        Activity

          [OBS-2901] graph.php showing zero agregate bps value for now in multi-port_bits* graphs

          It's working as it should. Thank you again.

          zidek@master.cz Martin Zídek added a comment - It's working as it should. Thank you again.

          Sorry , I will check it. Thank you.

          zidek@master.cz Martin Zídek added a comment - Sorry , I will check it. Thank you.
          adama Adam Armstrong added a comment - This is definitely fixed. http://demo.observium.org/graph.php?type=multi-port_bits_duo_separate&id=1072&idb=1173
          adama Adam Armstrong made changes -
          Status Original: Resolved [ 5 ] New: Closed [ 6 ]
          adama Adam Armstrong made changes -
          Comment [ Impatient, aren't we? ]
          adama Adam Armstrong made changes -
          Comment [ Any news on this ? ]

          I performed update  to 9701 and I see your fix with ADDNAN, but aggregate graphs still have zero value for Now. 

          zidek@master.cz Martin Zídek added a comment - I performed update  to 9701 and I see your fix with ADDNAN, but aggregate graphs still have zero value for Now. 
          adama Adam Armstrong made changes -
          Resolution New: Fixed [ 1 ]
          Status Original: Open [ 1 ] New: Resolved [ 5 ]

          This was apparently added in 2008, 2 years after i wrote the first graphs!

          adama Adam Armstrong added a comment - This was apparently added in 2008, 2 years after i wrote the first graphs!
          adama Adam Armstrong added a comment - - edited

          Aha. Apparently there is a special operator for this, because 1 + UNKNOWN = UNKNOWN, so they have a special operator where 1 + UNKNOWN = 1.

          It should behave better fin 9701.

          (this is literally a 12 year mystery solved!)

          adama Adam Armstrong added a comment - - edited Aha. Apparently there is a special operator for this, because 1 + UNKNOWN = UNKNOWN, so they have a special operator where 1 + UNKNOWN = 1. It should behave better fin 9701. (this is literally a 12 year mystery solved!)

          People

            adama Adam Armstrong
            zidek@master.cz Martin Zídek
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            Dates

              Created:
              Updated:
              Resolved: